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Last updated on August 29th, 2019 at 04:21 pm

In the main * Gravitation* article, we have shown the expressions for the gravitational potential for different situations. In our last article, we also have discussed and calculated the

*. Here we will discuss thoroughly the*

**Gravitational Potential due to Point Mass and Uniform Ring***Gravitational Potential Due to Spherical Shell*. We will also discuss the situation when the test point is outside of the shell as well as when it is inside the shell. Again, the main idea will be the calculation of work done to move a unit mass system from a point of reference to the field of influence of the source mass M.

## Gravitational Potential due to Spherical Shell

Let us consider a uniform spherical shell of mass M. The center of mass is located at point O. We have to calculate the potential due to this spherical system at a test point P, as shown in the figure below. We denote the distance between O and P as . By definition, the potential is the work done to move a unit mass from a point of reference, here infinity to the test point .

We will first draw a radius which makes an angle with the line . We will now draw a circle by keeping the central line OA fixed. The radius of this circle (see figure) is . Thus the perimeter of this circle will be . Now consider another circle with radius . These two circles form a ring (shown as green) having a mass of with a width of . Hence the area subtended by the ring is and the mass enclosed is

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Considering the triangle OAP, we can write and taking differential on both side, we find

Thus we can write the expression of in terms of as .

From our previous exercise, we know that the potential at a central point P due to the ring is

We can now use this expression to calculate gravitational potential due to spherical shell at a test point which is either outside of the shell or inside of the shell.

## Test Point P is Outside of the Shell

To calculate the potential at a point outside of the shell we have to integrate between to . This corresponds to *z=r-a* to *z=r+a*. Thus,

This is surprising to note that the expression for the potential due to spherical shell at an external point is identical to the expression of potential due to a point mass M situated at the center O of the shell.

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## Test Point P is Inside of the Shell

As shown in the figure, now we have a situation where corresponds to and corresponds to . Thus the potential due to the shell at an internal point can be calculated as,

Thus inside a uniform spherical shell, the gravitational potential is fixed and has a value of .

In the diagram below we have shown the gravitational potential due to a spherical shell as a function of distance from the center of the sphere.